Utilisateur:BSchaeffer~frwikiversity/Essais TeX et Latex

$\delta R_{ij}=\Gamma _{il}^{k}B_{k}dx^{l}$

Now consider arbitrary contravariant and covariant vectors $A^{i}$ and $B_{i}$ respectively. Since $A^{i}B_{i}$ is a scalar, $\delta (A^{i}B_{i})=0$, one arrives at:

$\Rightarrow \delta B_{i}=\Gamma _{il}^{k}B_{k}dx^{l}$

Connection Between Covariant And Regular Derivatives

$R_{xyxy}={\frac {1}{2}}\left(frac{\partial ^{2}g_{xx}}{\partial y^{2}}+{\frac {\partial ^{2}g_{xx}}{\partial y^{2}}}\right)$

$R_{xyxy}={\frac {1}{2}}\left({\frac {\partial ^{2}g_{xx}}{\partial y^{2}}}+{\frac {\partial ^{2}g_{xx}}{\partial y^{2}}}\right)$

$\Rightarrow \Gamma _{il}^{n}=\delta _{m}^{n}\Gamma _{il}^{m}={\frac {1}{2}}g^{kn}\left(g_{ik,l}+g_{kl,i}-g_{li,k}\right)$

$R_{x}yxy={\frac {1}{y^{2}}}$

\sqrt x=3 ${\sqrt {x}}=3$

$\int _{-n}^{n}e^{x}\$

$\int _{-n}^{n}e^{-x{2}}\mathrm {d} x$ $\int _{-n}^{n}e^{-x{2}}\mathrm {d} x$ // Aide de Julien1311 $\int _{-n}^{n}e^{-x{2}}\mathrm {d} x$

$\int _{-n}^{n}e^{-x{2}}\mathrm {d} x$

$\int _{-n}^{n}e^{x}\,\mathrm {d} x$

$a^{2}$

$\sum _{k=1}^{n}k^{2}$ OK

$\prod _{i=1}^{n}x_{i}$

${\begin{pmatrix}a&b\\c&d\end{pmatrix}}$

Intégrale double Échec de l’analyse (fonction inconnue « \begin{document} »): {\displaystyle \iint e^x}\, {\rm d}x {\rm d}y<math> <math>\iint e^{-\frac{x^2+y^2}{2}\, {\rm d}x {\rm d}y<math> \begin{document} \[\sum_{n=1}^{+\infty}\frac{1}{n^2}=\frac{\pi^2}{6}\] \end{document} <math> x_i }