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En raison de limitations techniques, la typographie souhaitable du titre, «
H, He, Hf, Hg, Hs, Ho : H, l'hydrogène Ensemble des formules chimiques/H, He, Hf, Hg, Hs, Ho/H, l'hydrogène », n'a pu être restituée correctement ci-dessus.
2
H
2
(
g
)
+
O
2
(
g
)
=
2
H
2
O
(
l
)
{\displaystyle {\rm {2H_{2(g)}+O_{2(g)}=2H_{2}O_{(l)}}}}
(bilan de réaction)
H
2
(
g
)
+
B
r
2
(
g
)
=
2
H
B
r
(
g
)
{\displaystyle {\rm {H_{2(g)}+Br_{2(g)}=2HBr_{(g)}}}}
avec ΔHo = 72.80 kJ ; ce bilan correspond à 5 étapes élémentaires:
B
r
2
+
M
→
k
1
2
B
r
∙
{\displaystyle \mathrm {Br} _{2}+\mathrm {M} \quad {\xrightarrow {k_{1}}}\quad 2\mathrm {Br} ^{\bullet }}
H
2
+
2
B
r
∙
→
k
2
B
r
∙
+
H
B
r
+
H
∙
{\displaystyle \mathrm {H} _{2}+\quad 2\mathrm {Br} ^{\bullet }\quad {\xrightarrow {k_{2}}}\quad \mathrm {Br} ^{\bullet }+\mathrm {HBr} +\mathrm {H} ^{\bullet }}
B
r
2
+
H
∙
→
k
3
B
r
∙
+
H
B
r
{\displaystyle \mathrm {Br} _{2}+\mathrm {H} ^{\bullet }\quad {\xrightarrow {k_{3}}}\quad \mathrm {Br} ^{\bullet }+\mathrm {HBr} }
H
B
r
+
H
∙
→
k
4
B
r
∙
+
H
2
{\displaystyle \mathrm {HBr} +\mathrm {H} ^{\bullet }\quad {\xrightarrow {k_{4}}}\quad \mathrm {Br} ^{\bullet }+\mathrm {H} _{2}}
B
r
∙
+
B
r
∙
+
M
→
k
5
B
r
2
{\displaystyle \mathrm {Br} ^{\bullet }+\mathrm {Br} ^{\bullet }+\mathrm {M} \quad {\xrightarrow {k_{5}}}\quad \mathrm {Br} _{2}}
H
2
+
Cl
2
⟶
2
HCl
{\displaystyle {\ce {H2 + Cl2 -> 2HCl}}}
3
H
2
+
N
2
⟶
2
NH
3
{\displaystyle {\ce {3H2 + N2 -> 2NH3}}}
H
(
aq
)
+
+
OH
−
(
aq
)
⟶
H
2
O
{\displaystyle {\ce {H^+_{(aq)}{}+ OH^-_{(aq)}-> H2O}}}
2
H
+
+
Mn
(
OH
)
2
⟶
Mn
2
+
+
2
HOH
{\displaystyle {\ce {2 H^{+}{}+ Mn(OH)2 -> Mn^{2+}{}+ 2HOH}}}
8
H
+
+
2
MnO
+
5
PbO
2
⟶
5
Pb
2
+
+
2
MnO
4
−
+
4
H
2
O
{\displaystyle {\ce {8 H^{+}{}+ 2 MnO + 5 PbO2 -> 5 Pb^{2+}{}+ 2 MnO4^{-}{}+ 4 H2O}}}
HCl
(
aq
)
+
KOH
(
aq
)
⟶
KCl
(
aq
)
+
H
2
O
(
l
)
{\displaystyle {\ce {HCl_{(aq)}{}+ KOH_{(aq)}{}-> KCl_{(aq)}{}+ H_2O_{(l)}{}}}}
2
HCl
(
aq
)
+
Fe
(
s
)
⟶
H
2
(
g
)
+
FeCl
2
(
aq
)
{\displaystyle {\ce {2 HCl_{(aq)}{}+ Fe_{(s)}-> H2_{(g)}{}+ FeCl2_{(aq)}}}}
12
H
C
l
O
4
+
P
4
O
10
→
4
H
3
P
O
4
+
6
C
l
2
O
7
{\displaystyle {\rm {12HClO_{4}+P_{4}O_{10}\to 4H_{3}PO_{4}+6Cl_{2}O_{7}}}}
10
H
N
O
3
+
2
M
n
O
+
5
P
b
O
2
→
5
P
b
(
N
O
3
)
2
+
2
H
M
n
O
4
+
4
H
2
O
{\displaystyle {\rm {10HNO_{3}+2MnO+5PbO_{2}\to 5Pb(NO_{3})_{2}+2HMnO_{4}+4H_{2}O}}}
HVO
4
2
−
+
H
+
⟶
H
2
VO
4
−
{\displaystyle {\ce {HVO4^{2-}{}+ H+ -> H2VO4^-}}}
3
H
2
(
g
)
+
N
2
(
g
)
⟶
2
N
−
III
H
3
(
g
)
I
{\displaystyle {\ce {3 H2_{(g)}{}+ N2_{(g)}-> 2 N^{-III}H^{I}3_{(g)}}}}
2
H
2
(
g
)
+
O
2
(
g
)
⟶
2
H
2
O
(
g
)
{\displaystyle {\ce {2H2_{(g)}{}+ O2_{(g)}-> 2H2O_{(g)}}}}
H
2
CO
3
⟶
HCO
3
(
aq
)
−
+
H
(
aq
)
+
{\displaystyle {\ce {H2CO3 -> HCO3_{(aq)}^{-}{}+ H^{+}_{(aq)}}}}
H
2
CO
3
(
aq
)
⟶
H
2
O
(
l
)
+
CO
2
(
g
)
{\displaystyle {\ce {H2CO3_{(aq)}-> H2O_{(l)}{}+ CO2_{(g)}}}}
H
2
O
+
Na
2
O
⟶
2
NaOH
{\displaystyle {\ce {H2O + Na2O -> 2 NaOH}}}
H
2
O
+
CO
2
(
g
)
⟶
H
2
CO
3
(
aq
)
{\displaystyle {\ce {H2 O +CO2_{(g)}-> H2CO3_{(aq)}}}}
H
2
O
+
Si
2
Al
2
O
5
(
O
H
)
4
⟶
2
Si
O
2
(
aq
)
+
2
Al
(
O
H
)
3
{\displaystyle {\ce {H_2 O + Si_2 Al_2 O_5 ( O H )_4 -> 2 Si O2_{(aq)}{}+ 2 Al ( O H )_3}}}
H
2
S
−
II
+
2
Fe
III
Cl
3
⟶
2
HCl
+
S
+
2
Fe
II
Cl
2
{\displaystyle {\ce {H2S^{-II}{}+ 2 Fe^{III}Cl3 -> 2 HCl + S + 2 Fe^{II}Cl2}}}
3
H
2
SO
4
(
aq
)
+
2
KMn
VII
O
4
(
aq
)
+
5
H
2
O
2
(
aq
)
−
I
⟶
8
H
2
O
(
l
)
+
5
O
2
(
g
)
+
K
2
SO
4
(
aq
)
+
2
Mn
II
SO
4
(
aq
)
{\displaystyle {\ce {3 H_2SO_4_{(aq)}{}+ 2 KMn^{VII}O_4_{(aq)}{}+ 5 H_2O^{-I}_2_{(aq)}-> 8 H_2O_{(l)}{}+ 5 O2_{(g)}{}+ K_2SO_4_{(aq)}{}+ 2 Mn^{II}SO_4_{(aq)}}}}
3
H
2
I
SO
4
(
aq
)
+
2
Al
(
s
)
⟶
3
H
2
(
g
)
+
Al
2
III
(
SO
4
)
3
(
aq
)
{\displaystyle {\ce {3 H^{I}2SO4_{(aq)}{}+ 2 Al_{(s)}{}-> 3 H2_{(g)}{}+ Al^{III}2(SO4)3_{(aq)}{}}}}
8
H
2
SO
4
(
aq
)
+
2
KMn
VII
O
4
(
aq
)
+
10
Fe
II
SO
4
(
aq
)
⟶
8
H
2
O
(
l
)
+
K
2
SO
4
(
aq
)
+
2
Mn
II
SO
4
(
aq
)
+
5
Fe
2
III
(
SO
4
)
3
(
s
)
{\displaystyle {\ce {8 H_2SO_4_{(aq)}{}+ 2 KMn^{VII}O_4_{(aq)}{}+ 10 Fe^{II}SO_4_{(aq)}-> 8 H_2O_{(l)}{}+ K_2SO_4_{(aq)}{}+ 2 Mn^{II}SO_4_{(aq)}{}+ 5 Fe^{III}_2(SO_4)_3_{(s)}}}}
H
2
VO
4
−
+
2
H
+
⟶
VO
2
+
+
2
HOH
{\displaystyle {\ce {H2VO4^{-}{}+ 2H+ -> VO2^{+}{}+ 2HOH}}}